# Merton 76 Closed-Form Solution¶

## Overview¶

One of the assumptions in the Black Scholes model is that the stock price moves as geometric Brownian Motion. In reality the stock price will have ‘jumps’ due to events such as takeover announcements and court actions. Merton’s Jump Diffusion Model does this by superimposing a jump component on the Black Scholes Diffusion Component. This Jump Component is composed of log-normal jumps driven by a Poisson process.

An equation can be derived for the resulting Call Option price:

$F(S,\tau) = \sum_{n=0}^{\infty} \frac{\mathrm{e}^{-\lambda\tau}(\lambda\tau)^n}{n!} \left[\epsilon_n\lbrace W(SX_n\mathrm{e}^{-\lambda k\tau},\tau ;E,\sigma^2,r)\rbrace\right]$

where W is the standard Black Scholes formula and $$X_n$$ is a complicated random variable which is out of the scope of this explanation. This is very difficult to solve but Merton came up with a specific case where $$X_n$$ has a log-normal distribution. This simplifies the closed form call price solution to:

$F(S,\tau) = \sum_{n=0}^{\infty} \frac{\mathrm{e}^{-\lambda^{'}\tau}(\lambda^{'}\tau)^n}{n!} W_n(S,\tau ;E,v_n^2,r_n)$
$v_n^2 = \left[\sigma^2 + n\delta^2 / \tau \right]$
$r_n = r - \lambda k + n \gamma / \tau$

where:

S = stock price

E = strike price

$$X_n$$ = complicated random variable!

$$\tau$$ = time to maturity

$$\lambda$$ = mean jump count per unit time

$$\lambda^{'}$$ = $$\lambda' (1+k)$$

$$\sigma$$ = volatility

$$\delta^2$$ = variance of ln ($$\gamma$$)

r = interest rate

k = Expected($$\gamma$$ -1)

$$\gamma$$ = random Poisson variable